1073. Adding Two Negabinary Numbers
Given two numbers arr1 and arr2 in base -2, return the result of adding them together.
Each number is given in array format: as an array of 0s and 1s, from most significant bit to least significant bit. For example, arr = [1,1,0,1] represents the number (-2)^3 + (-2)^2 + (-2)^0 = -3. A number arr in array, format is also guaranteed to have no leading zeros: either arr == [0] or arr[0] == 1.
Return the result of adding arr1 and arr2 in the same format: as an array of 0s and 1s with no leading zeros.
Example 1:
Input: arr1 = [1,1,1,1,1], arr2 = [1,0,1] Output: [1,0,0,0,0] Explanation: arr1 represents 11, arr2 represents 5, the output represents 16.
Example 2:
Input: arr1 = [0], arr2 = [0] Output: [0]
Example 3:
Input: arr1 = [0], arr2 = [1] Output: [1]
Constraints:
1 <= arr1.length, arr2.length <= 1000arr1[i]andarr2[i]are0or1arr1andarr2have no leading zeros
Rust Solution
struct Solution;
impl Solution {
fn add_negabinary(mut arr1: Vec<i32>, mut arr2: Vec<i32>) -> Vec<i32> {
let n = arr1.len();
let m = arr2.len();
arr1.reverse();
arr2.reverse();
let mut carry = 0;
let mut res = vec![];
let mut i = 0;
while i < n.max(m) || carry != 0 {
if i < n {
carry += arr1[i];
}
if i < m {
carry += arr2[i];
}
res.push(carry & 1);
carry = -(carry >> 1);
i += 1;
}
while let Some(&0) = res.last() {
res.pop();
}
res.reverse();
if res.is_empty() {
vec![0]
} else {
res
}
}
}
#[test]
fn test() {
let arr1 = vec![1, 1, 1, 1, 1];
let arr2 = vec![1, 0, 1];
let res = vec![1, 0, 0, 0, 0];
assert_eq!(Solution::add_negabinary(arr1, arr2), res);
let arr1 = vec![1];
let arr2 = vec![1];
let res = vec![1, 1, 0];
assert_eq!(Solution::add_negabinary(arr1, arr2), res);
let arr1 = vec![1];
let arr2 = vec![1, 1];
let res = vec![0];
assert_eq!(Solution::add_negabinary(arr1, arr2), res);
}
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