RUST GYM Leetcode 1271 Hexspeak Rust Solution

1271. Hexspeak

A decimal number can be converted to its Hexspeak representation by first converting it to an uppercase hexadecimal string, then replacing all occurrences of the digit 0 with the letter O, and the digit 1 with the letter I. Such a representation is valid if and only if it consists only of the letters in the set {"A", "B", "C", "D", "E", "F", "I", "O"}.

Given a string num representing a decimal integer N, return the Hexspeak representation of N if it is valid, otherwise return "ERROR".

Example 1:

Input: num = "257"
Output: "IOI"
Explanation:  257 is 101 in hexadecimal.

Example 2:

Input: num = "3"
Output: "ERROR"

Constraints:

1 <= N <= 10^12
There are no leading zeros in the given string.
All answers must be in uppercase letters.

Rust Solution

struct Solution;

#[allow(clippy::wrong_self_convention)]
impl Solution {
    fn to_hexspeak(num: String) -> String {
        let x: i64 = num.parse::<i64>().unwrap();
        let s = format!("{:X}", x);
        let mut res: Vec<char> = vec![];
        for c in s.chars() {
            match c {
                '0' => res.push('O'),
                '1' => res.push('I'),
                c @ 'A'..='F' => res.push(c),
                _ => return "ERROR".to_string(),
            }
        }
        res.iter().collect()
    }
}

#[test]
fn test() {
    let num = "257".to_string();
    let res = "IOI".to_string();
    assert_eq!(Solution::to_hexspeak(num), res);
    let num = "3".to_string();
    let res = "ERROR".to_string();
    assert_eq!(Solution::to_hexspeak(num), res);
    let num = "619879596177".to_string();
    let res = "ERROR".to_string();
    assert_eq!(Solution::to_hexspeak(num), res);
}

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