Given two numbers, hour and minutes. Return the smaller angle (in degrees) formed between the hour and the minute hand.
Example 1:
Input: hour = 12, minutes = 30 Output: 165
Example 2:
Input: hour = 3, minutes = 30 Output: 75
Example 3:
Input: hour = 3, minutes = 15 Output: 7.5
Example 4:
Input: hour = 4, minutes = 50 Output: 155
Example 5:
Input: hour = 12, minutes = 0 Output: 0
Constraints:
1 <= hour <= 120 <= minutes <= 59- Answers within
10^-5of the actual value will be accepted as correct.
struct Solution;
impl Solution {
fn angle_clock(hour: i32, minutes: i32) -> f64 {
let h = ((hour % 12) as f64 + (minutes as f64 / 60.0)) * 30.0;
let m = minutes as f64 * 6.0;
let a = (h - m).abs();
if a > 180.0 {
360.0 - a
} else {
a
}
}
}
#[test]
fn test() {
use assert_approx_eq::assert_approx_eq;
let hour = 12;
let minutes = 30;
let res = 165.0;
assert_approx_eq!(Solution::angle_clock(hour, minutes), res);
let hour = 3;
let minutes = 30;
let res = 75.0;
assert_approx_eq!(Solution::angle_clock(hour, minutes), res);
let hour = 3;
let minutes = 15;
let res = 7.5;
assert_approx_eq!(Solution::angle_clock(hour, minutes), res);
let hour = 4;
let minutes = 50;
let res = 155.0;
assert_approx_eq!(Solution::angle_clock(hour, minutes), res);
let hour = 12;
let minutes = 0;
let res = 0.0;
assert_approx_eq!(Solution::angle_clock(hour, minutes), res);
let hour = 1;
let minutes = 57;
let res = 76.5;
assert_approx_eq!(Solution::angle_clock(hour, minutes), res);
}