RUST GYM Leetcode 167 Two Sum II - Input array is sorted Rust Solution

167. Two Sum II - Input array is sorted

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.

The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2.

Note:

Your returned answers (both index1 and index2) are not zero-based.
You may assume that each input would have exactly one solution and you may not use the same element twice.

Example 1:

Input: numbers = [2,7,11,15], target = 9
Output: [1,2]
Explanation: The sum of 2 and 7 is 9. Therefore index1 = 1, index2 = 2.

Example 2:

Input: numbers = [2,3,4], target = 6
Output: [1,3]

Example 3:

Input: numbers = [-1,0], target = -1
Output: [1,2]

Constraints:

2 <= nums.length <= 3 * 10⁴
-1000 <= nums[i] <= 1000
nums is sorted in increasing order.
-1000 <= target <= 1000

Rust Solution

struct Solution;

impl Solution {
    fn two_sum(nums: Vec<i32>, target: i32) -> Vec<i32> {
        let mut left: usize = 0;
        let mut right: usize = nums.len() - 1;
        while left < right {
            if nums[left] + nums[right] == target {
                return vec![(left + 1) as i32, (right + 1) as i32];
            }
            if nums[left] + nums[right] < target {
                left += 1;
                continue;
            }
            if nums[left] + nums[right] > target {
                right -= 1;
                continue;
            }
        }
        vec![0, 0]
    }
}

#[test]
fn test() {
    assert_eq!(Solution::two_sum(vec![2, 7, 11, 15], 9), vec![1, 2]);
}

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