## 1685. Sum of Absolute Differences in a Sorted Array

You are given an integer array `nums`

sorted in **non-decreasing** order.

Build and return *an integer array *`result`

* with the same length as *`nums`

* such that *`result[i]`

* is equal to the summation of absolute differences between *

`nums[i]`

*and all the other elements in the array.*

In other words, `result[i]`

is equal to `sum(|nums[i]-nums[j]|)`

where `0 <= j < nums.length`

and `j != i`

(**0-indexed**).

**Example 1:**

Input:nums = [2,3,5]Output:[4,3,5]Explanation:Assuming the arrays are 0-indexed, then result[0] = |2-2| + |2-3| + |2-5| = 0 + 1 + 3 = 4, result[1] = |3-2| + |3-3| + |3-5| = 1 + 0 + 2 = 3, result[2] = |5-2| + |5-3| + |5-5| = 3 + 2 + 0 = 5.

**Example 2:**

Input:nums = [1,4,6,8,10]Output:[24,15,13,15,21]

**Constraints:**

`2 <= nums.length <= 10`

^{5}`1 <= nums[i] <= nums[i + 1] <= 10`

^{4}

## Rust Solution

```
struct Solution;
impl Solution {
fn get_sum_absolute_differences(nums: Vec<i32>) -> Vec<i32> {
let n = nums.len();
let mut prev = nums[0];
let mut prev_sum = 0;
let mut res = vec![0; n];
for i in 0..n {
let diff = nums[i] - prev;
prev_sum += diff * i as i32;
res[i] += prev_sum;
prev = nums[i];
}
prev = nums[n - 1];
prev_sum = 0;
for i in (0..n).rev() {
let diff = (nums[i] - prev).abs();
prev_sum += diff * (n - 1 - i) as i32;
res[i] += prev_sum;
prev = nums[i];
}
res
}
}
#[test]
fn test() {
let nums = vec![2, 3, 5];
let res = vec![4, 3, 5];
assert_eq!(Solution::get_sum_absolute_differences(nums), res);
let nums = vec![1, 4, 6, 8, 10];
let res = vec![24, 15, 13, 15, 21];
assert_eq!(Solution::get_sum_absolute_differences(nums), res);
}
```

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