Given a 0-indexed integer array nums
, return true
if it can be made strictly increasing after removing exactly one element, or false
otherwise. If the array is already strictly increasing, return true
.
The array nums
is strictly increasing if nums[i - 1] < nums[i]
for each index (1 <= i < nums.length).
Example 1:
Input: nums = [1,2,10,5,7] Output: true Explanation: By removing 10 at index 2 from nums, it becomes [1,2,5,7]. [1,2,5,7] is strictly increasing, so return true.
Example 2:
Input: nums = [2,3,1,2] Output: false Explanation: [3,1,2] is the result of removing the element at index 0. [2,1,2] is the result of removing the element at index 1. [2,3,2] is the result of removing the element at index 2. [2,3,1] is the result of removing the element at index 3. No resulting array is strictly increasing, so return false.
Example 3:
Input: nums = [1,1,1] Output: false Explanation: The result of removing any element is [1,1]. [1,1] is not strictly increasing, so return false.
Example 4:
Input: nums = [1,2,3] Output: true Explanation: [1,2,3] is already strictly increasing, so return true.
Constraints:
2 <= nums.length <= 1000
1 <= nums[i] <= 1000
struct Solution;
impl Solution {
fn can_be_increasing(nums: Vec<i32>) -> bool {
let n = nums.len();
for i in 0..n {
let mut v = vec![];
for j in 0..n {
if i == j {
continue;
}
v.push(nums[j]);
}
if Self::is_increasing(&v) {
return true;
}
}
false
}
fn is_increasing(nums: &[i32]) -> bool {
let n = nums.len();
for i in 1..n {
if nums[i] <= nums[i - 1] {
return false;
}
}
true
}
}
#[test]
fn test() {
let nums = vec![1, 2, 10, 5, 7];
let res = true;
assert_eq!(Solution::can_be_increasing(nums), res);
let nums = vec![2, 3, 1, 2];
let res = false;
assert_eq!(Solution::can_be_increasing(nums), res);
let nums = vec![1, 1, 1];
let res = false;
assert_eq!(Solution::can_be_increasing(nums), res);
let nums = vec![1, 2, 3];
let res = true;
assert_eq!(Solution::can_be_increasing(nums), res);
}