## 378. Kth Smallest Element in a Sorted Matrix

Given a n x n matrix where each of the rows and columns are sorted in ascending order, find the kth smallest element in the matrix.

Note that it is the kth smallest element in the sorted order, not the kth distinct element.

Example:

```matrix = [
[ 1,  5,  9],
[10, 11, 13],
[12, 13, 15]
],
k = 8,

return 13.
```

Note:
You may assume k is always valid, 1 ≤ k ≤ n2.

## Rust Solution

``````struct Solution;
use std::collections::BinaryHeap;

impl Solution {
fn kth_smallest(matrix: Vec<Vec<i32>>, k: i32) -> i32 {
let mut pq: BinaryHeap<i32> = BinaryHeap::new();
for row in matrix {
for x in row {
pq.push(x);
if pq.len() > k as usize {
pq.pop();
}
}
}
pq.pop().unwrap()
}
}

#[test]
fn test() {
let matrix = vec_vec_i32![[1, 5, 9], [10, 11, 13], [12, 13, 15]];
let k = 8;
let res = 13;
assert_eq!(Solution::kth_smallest(matrix, k), res);
let matrix = vec_vec_i32![[1, 2], [1, 3]];
let k = 3;
let res = 2;
assert_eq!(Solution::kth_smallest(matrix, k), res);
}
``````

Having problems with this solution? Click here to submit an issue on github.