Given an input string (s) and a pattern (p), implement wildcard pattern matching with support for '?' and '*' where:
'?' Matches any single character.'*' Matches any sequence of characters (including the empty sequence).The matching should cover the entire input string (not partial).
Example 1:
Input: s = "aa", p = "a" Output: false Explanation: "a" does not match the entire string "aa".
Example 2:
Input: s = "aa", p = "*" Output: true Explanation: '*' matches any sequence.
Example 3:
Input: s = "cb", p = "?a" Output: false Explanation: '?' matches 'c', but the second letter is 'a', which does not match 'b'.
Example 4:
Input: s = "adceb", p = "*a*b" Output: true Explanation: The first '*' matches the empty sequence, while the second '*' matches the substring "dce".
Example 5:
Input: s = "acdcb", p = "a*c?b" Output: false
Constraints:
0 <= s.length, p.length <= 2000s contains only lowercase English letters.p contains only lowercase English letters, '?' or '*'.struct Solution;
impl Solution {
fn is_match(s: String, p: String) -> bool {
let n = s.len();
let m = p.len();
let s: Vec<char> = s.chars().collect();
let p: Vec<char> = p.chars().collect();
let mut memo: Vec<Vec<Option<bool>>> = vec![vec![None; m + 1]; n + 1];
Self::is_match_dp(n, m, &mut memo, &s, &p)
}
fn is_match_dp(
n: usize,
m: usize,
memo: &mut Vec<Vec<Option<bool>>>,
s: &[char],
p: &[char],
) -> bool {
if let Some(ans) = memo[n][m] {
ans
} else {
let res = if n == 0 && m == 0 {
true
} else if n == 0 && m != 0 {
if p[m - 1] == '*' {
Self::is_match_dp(n, m - 1, memo, s, p)
} else {
false
}
} else if n != 0 && m == 0 {
false
} else {
if s[n - 1] == p[m - 1] {
Self::is_match_dp(n - 1, m - 1, memo, s, p)
} else {
match p[m - 1] {
'?' => Self::is_match_dp(n - 1, m - 1, memo, s, p),
'*' => {
Self::is_match_dp(n - 1, m, memo, s, p)
|| Self::is_match_dp(n, m - 1, memo, s, p)
}
_ => false,
}
}
};
memo[n][m] = Some(res);
res
}
}
}
#[test]
fn test() {
let s = "aa".to_string();
let p = "a".to_string();
let res = false;
assert_eq!(Solution::is_match(s, p), res);
let s = "aa".to_string();
let p = "*".to_string();
let res = true;
assert_eq!(Solution::is_match(s, p), res);
let s = "cb".to_string();
let p = "?a".to_string();
let res = false;
assert_eq!(Solution::is_match(s, p), res);
let s = "adceb".to_string();
let p = "*a*b".to_string();
let res = true;
assert_eq!(Solution::is_match(s, p), res);
let s = "acdcb".to_string();
let p = "a*c?b".to_string();
let res = false;
assert_eq!(Solution::is_match(s, p), res);
}