Implement pow(x, n), which calculates x raised to the power n (i.e. xn).
Example 1:
Input: x = 2.00000, n = 10 Output: 1024.00000
Example 2:
Input: x = 2.10000, n = 3 Output: 9.26100
Example 3:
Input: x = 2.00000, n = -2 Output: 0.25000 Explanation: 2-2 = 1/22 = 1/4 = 0.25
Constraints:
-100.0 < x < 100.0
-231 <= n <= 231-1
-104 <= xn <= 104
struct Solution;
impl Solution {
fn my_pow(x: f64, n: i32) -> f64 {
x.powi(n)
}
}
#[test]
fn test() {
use assert_approx_eq::assert_approx_eq;
assert_approx_eq!(Solution::my_pow(2.0, 10), 1024.0);
assert_approx_eq!(Solution::my_pow(2.0, -3), 0.125);
assert_approx_eq!(Solution::my_pow(1.0, -2_147_483_648), 1.0);
}