We define a harmonious array as an array where the difference between its maximum value and its minimum value is **exactly** `1`

.

Given an integer array `nums`

, return *the length of its longest harmonious subsequence among all its possible subsequences*.

A **subsequence** of array is a sequence that can be derived from the array by deleting some or no elements without changing the order of the remaining elements.

**Example 1:**

Input:nums = [1,3,2,2,5,2,3,7]Output:5Explanation:The longest harmonious subsequence is [3,2,2,2,3].

**Example 2:**

Input:nums = [1,2,3,4]Output:2

**Example 3:**

Input:nums = [1,1,1,1]Output:0

**Constraints:**

`1 <= nums.length <= 2 * 10`

^{4}`-10`

^{9}<= nums[i] <= 10^{9}

```
struct Solution;
use std::collections::HashMap;
impl Solution {
fn find_lhs(nums: Vec<i32>) -> i32 {
let mut hs: HashMap<i32, i32> = HashMap::new();
let mut max = 0;
for &x in &nums {
let e = hs.entry(x).or_default();
*e += 1;
}
for (x, u) in &hs {
if let Some(v) = hs.get(&(x - 1)) {
max = i32::max(u + v, max);
}
}
max
}
}
#[test]
fn test() {
let nums = vec![1, 3, 2, 2, 5, 2, 3, 7];
let res = 5;
assert_eq!(Solution::find_lhs(nums), res);
}
```