RUST GYM Leetcode 680 Valid Palindrome II Rust Solution

680. Valid Palindrome II

Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome.

Example 1:

Input: "aba"
Output: True

Example 2:

Input: "abca"
Output: True
Explanation: You could delete the character 'c'.

Note:

The string will only contain lowercase characters a-z. The maximum length of the string is 50000.

Rust Solution

struct Solution;

impl Solution {
    fn valid_palindrome(s: String) -> bool {
        let v: &str = s.as_str();
        if let Some(s) = Solution::is_palidrome(v) {
            let sl: &str = &s[1..];
            let sr: &str = &s[..s.len() - 1];
            Self::is_palidrome(sl).is_none() || Self::is_palidrome(sr).is_none()
        } else {
            true
        }
    }

    fn is_palidrome(v: &str) -> Option<&str> {
        let n = v.len();
        if n <= 1 {
            return None;
        }
        if v.chars().next() != v.chars().last() {
            Some(v)
        } else {
            Self::is_palidrome(&v[1..n - 1])
        }
    }
}

#[test]
fn test() {
    let s = "aba".to_string();
    assert_eq!(Solution::valid_palindrome(s), true);
    let s = "abca".to_string();
    assert_eq!(Solution::valid_palindrome(s), true);
    let s = "accca".to_string();
    assert_eq!(Solution::valid_palindrome(s), true);
}

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