## 739. Daily Temperatures

Given a list of daily temperatures `T`, return a list such that, for each day in the input, tells you how many days you would have to wait until a warmer temperature. If there is no future day for which this is possible, put `0` instead.

For example, given the list of temperatures `T = [73, 74, 75, 71, 69, 72, 76, 73]`, your output should be `[1, 1, 4, 2, 1, 1, 0, 0]`.

Note: The length of `temperatures` will be in the range `[1, 30000]`. Each temperature will be an integer in the range `[30, 100]`.

## Rust Solution

``````struct Solution;

impl Solution {
fn daily_temperatures(t: Vec<i32>) -> Vec<i32> {
let mut res: Vec<i32> = vec![];
let mut stack: Vec<usize> = vec![];
let n = t.len();
for i in (0..n).rev() {
while let Some(j) = stack.pop() {
if t[j] > t[i] {
stack.push(j);
break;
}
}
if let Some(j) = stack.last() {
res.push((j - i) as i32);
} else {
res.push(0);
}
stack.push(i)
}
res.into_iter().rev().collect()
}
}

#[test]
fn test() {
let t = vec![73, 74, 75, 71, 69, 72, 76, 73];
let res = vec![1, 1, 4, 2, 1, 1, 0, 0];
assert_eq!(Solution::daily_temperatures(t), res);
}
``````

Having problems with this solution? Click here to submit an issue on github.