RUST GYM Leetcode 889 Construct Binary Tree from Preorder and Postorder Traversal Rust Solution

889. Construct Binary Tree from Preorder and Postorder Traversal

Return any binary tree that matches the given preorder and postorder traversals.

Values in the traversals pre and post are distinct positive integers.

Example 1:

Input: pre = [1,2,4,5,3,6,7], post = [4,5,2,6,7,3,1]
Output: [1,2,3,4,5,6,7]

Note:

1 <= pre.length == post.length <= 30
pre[] and post[] are both permutations of 1, 2, ..., pre.length.
It is guaranteed an answer exists. If there exists multiple answers, you can return any of them.

Rust Solution

struct Solution;
use rustgym_util::*;

impl Solution {
    fn construct_from_pre_post(pre: Vec<i32>, post: Vec<i32>) -> TreeLink {
        Self::build(&mut 0, &mut 0, &pre, &post)
    }

    fn build(i: &mut usize, j: &mut usize, pre: &[i32], post: &[i32]) -> TreeLink {
        let val = pre[*i];
        *i += 1;
        let mut left = None;
        let mut right = None;
        if val != post[*j] {
            left = Self::build(i, j, pre, post);
        }
        if val != post[*j] {
            right = Self::build(i, j, pre, post);
        }
        *j += 1;
        tree!(val, left, right)
    }
}

#[test]
fn test() {
    let pre = vec![1, 2, 4, 5, 3, 6, 7];
    let post = vec![4, 5, 2, 6, 7, 3, 1];
    let res = tree!(
        1,
        tree!(2, tree!(4), tree!(5)),
        tree!(3, tree!(6), tree!(7))
    );
    assert_eq!(Solution::construct_from_pre_post(pre, post), res);
}

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