974. Subarray Sums Divisible by K

Given an array A of integers, return the number of (contiguous, non-empty) subarrays that have a sum divisible by K.

 

Example 1:

Input: A = [4,5,0,-2,-3,1], K = 5
Output: 7
Explanation: There are 7 subarrays with a sum divisible by K = 5:
[4, 5, 0, -2, -3, 1], [5], [5, 0], [5, 0, -2, -3], [0], [0, -2, -3], [-2, -3]

 

Note:

  1. 1 <= A.length <= 30000
  2. -10000 <= A[i] <= 10000
  3. 2 <= K <= 10000

974. Subarray Sums Divisible by K
struct Solution;

impl Solution {
    fn subarrays_div_by_k(a: Vec<i32>, k: i32) -> i32 {
        let n = k as usize;
        let mut count: Vec<i32> = vec![0; n];
        let mut sum = 0;
        let mut res = 0;
        count[0] = 1;
        for x in a {
            sum = (sum + x % k + k) % k;
            res += count[sum as usize];
            count[sum as usize] += 1;
        }
        res
    }
}

#[test]
fn test() {
    let a = vec![4, 5, 0, -2, -3, 1];
    let k = 5;
    let res = 7;
    assert_eq!(Solution::subarrays_div_by_k(a, k), res);
}